**Oh dear: this instalment was intended to be a routine exposition of the special case when p=7 of the reasoning contained in the second part of Blog 2 (2022) which introduced the exciting new elementary approach to Fermat’s lost theorem. The point of focusing onto this special case was to illuminate the core argument, which can be understood much more easily when we are dealing with a specific value of p. Unfortunately a problem has emerged at the last moment.**

The Main Case of Fermat’s Enigma concerns the possibility that his (Fermat’s) equation harbours a contradiction when T* _{ab}* > 0 (mod

But work on the Minor Case when T* _{ab}* = 0 (mod

[When *A*=0, *Y* becomes *b*^{4}/7*V* which is an irrational number because *V* becomes the 7^{th} root of *b*^{4}/117649. *L* too becomes an irrational number because it, too, is defined in terms of *V*. (In Blog 2 *Y* and *L* were used to denote the specific unknown numbers which obtained when the *A*s in their specific defining expressions were replaced by zeros.) The result of this was, regrettably, overlooked in Blog 2. But now, using the correct expressions for *Y* and *L *instead, it can be clearly seen that the expression above (*Y* ^{p}– *pL*^{p}*b*^{p-3}) —which was supposedly an expression composed of natural numbers— ends up being equal to *b*^{4}* – b*^{4}! This shows unmistakably that *Y* ^{p}– *p**L*^{p}*b*^{p-3} is zero, and that *Y* ^{p}– *p**L*^{p}*b*^{p-3} *does have* the factor *A*! With the advantages of hindsight it is obvious that that, if one takes away the one and only non-*A* term in a polynomial, the result will be that what remains has the factor *A*.]

This glitch does not invalidate the reasoning in the main case, when T* _{ab}* > 0 (mod

The same strategy underlying the main case when T* _{ab}* > 0 (mod

**A Glitch Review** Careful followers of this series of Blogs will have already noticed that a succession of glitches occurred when the extraordinary Enigma discovered by Richard Beetham —the author’s former teacher in 1946— was picked up in the *Mathematical Gazette* in 2020. The Beetham Enigma was actually much more difficult to resolve than this current hitch in dealing with Fermat’s Enigma. This arose from the fact that there was no apparent reason why the Beetham Enigma was so difficult. The author is now rather old, and he has outlived virtually all his former mathematical friends —who might otherwise have been able to check his reasoning with unbiased eyes. It took him more than two years —during which he explored more than 300 possible elementary constructions in vain— to put together a strategy for tackling the Beetham Enigma. Several of these suggested paths of reasoning which were aired in these Blogs but subsequently turned out to be glitched. The solution was to base the reasoning on a strategy which amplified an unobvious overall symmetry in the configuration. There is actually also a minor glitch in the final Beetham Blog (the point marked E in the last diagram is not the same as the point marked E in the earlier diagrams) but this has no effect on the reasoning, so it is not significant.

**CHRISTOPHER ORMELL June 1 ^{st} 2022 **